or
or
If the average of 'm' numbers is n2 and that of 'n' numbers is m2, then the average of (m + n) numbers is -
Average of m numbers n^2
So, Sum of m numbers= mn^2
Average of n numbers m^2
So, sum of n numbers= nm^2
Now,
Sum of (m+n) numbers= mn^2+nm^2 = mn(m+n)
Average of (m+n) numbers= {mn(m+n)}/(m+n) = mn
Ans: mn
average =
avergae of ‘m’ numbers is n2 = so, sum of m = mn2
average of ‘n’ number is m2 = so, sum of n =nm2
average of m+n =
=
=
= mn (Ans)
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